2015 Ontario GTA Photo Tag | Page 60 | GTAMotorcycle.com

2015 Ontario GTA Photo Tag

Old:
Queen and Hastings, Toronto
Ag6vI9O.jpg
 
New:
In here, no matter where you run, the Warden is always close by.
jif10hi.jpg
 
I'm in on the gag with DDean; the old tag is still good.

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yeah, last year your pic was the new and mine was the old. Ahhh the good ol days...
 
NEW:

(sorry, got stuck in traffic)

zEPuD52.png


Let me know if you want the coordinates
 
Last edited:
Yes, please.

But not that easy Hehehe...



LAT: Square root of 1958.1 = "x" (NORTH)




3517.22
LON: _______________________= "y" (WEST)
x


Plug in the numbers as per latitude, longitude convention in any map application.

Voilà
 
Last edited:
But not that easy Hehehe...



LAT: Square root of 1958.1 = "x" (NORTH)




3517.22
LON: _______________________= "y" (WEST)
x


Plug in the numbers as per latitude, longitude convention in any map application.

Voilà

Uh bro that puts me in Asia. And if I swap a negative in front of the LONG value it puts me off the coast of Nova Scotia. Definitely out of boundaries ;)

44.25042372678481, -59.30615482393037
 
Uh bro that puts me in Asia. And if I swap a negative in front of the LONG value it puts me off the coast of Nova Scotia. Definitely out of boundaries ;)

44.25042372678481, -59.30615482393037
I think you forgot to carry the 2. ?

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Uh bro that puts me in Asia. And if I swap a negative in front of the LONG value it puts me off the coast of Nova Scotia. Definitely out of boundaries ;)

44.25042372678481, -59.30615482393037

The math is sound, check the process bro

There are no negatives.
 
Goddamn show me it in equation form! It's Sunday damnit

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Cmon Macs, just ride to every street entering Keswick, its a good day, you'll find it eventually! Keswick ain't THAT big *that's what I'm doing if this is really still up during the week ahahahaha
 
Old: 44.25042372678481,-79.48443661729333

4232d75815f654d67f6c24933be80555.jpg


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New:

0b0abd441fc467088324529b810036f0.jpg


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Lol, you got the first number right, that's "x". Replace it in the other equation and you got the answer.
I get the first part, but I ain't no math genius. Can you explain the second part, please?

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